The following are the times, in minutes, taken by 11 runners to complete a 10 km run.
48.3, 55.2, 59.9, 67.7, 60.5, 75.6, 62.5, 57.4, 53.4, 49.2, 64.1
Find the mean and standard deviation of these times.
Solution
To find the mean, use the formula:
\(\bar{x} = \frac{\sum x}{n}\)
\(\bar{x} = \frac{48.3 + 55.2 + 59.9 + 67.7 + 60.5 + 75.6 + 62.5 + 57.4 + 53.4 + 49.2 + 64.1}{11} = 59.4\)
To find the standard deviation, use the formula:
\(\sigma = \sqrt{\frac{\sum (x - \bar{x})^2}{n}}\)
Calculate each squared deviation:
\((48.3 - 59.4)^2, (55.2 - 59.4)^2, (59.9 - 59.4)^2, \ldots, (64.1 - 59.4)^2\)
Sum these squared deviations:
\(\sum (x - \bar{x})^2 = 646.64\)
Then, \(\sigma = \sqrt{\frac{646.64}{11}} = 7.68\)
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