Represent this information on a back-to-back stem-and-leaf diagram.
Find the median and the interquartile range of the lengths of the diagonals of the 9 conventional TVs.
Find the mean and standard deviation of the lengths of the diagonals of the 9 flat screen TVs.
Solution
(i) The back-to-back stem-and-leaf diagram is constructed as follows:
Flat screen
conventional
6421
6
579
6
7
1457
95
8
56
74
9
10
Key: \( 5 \mid 8 \mid 4 \) means \( 0.85 \) m for flat screen.
(ii) To find the median of the conventional TVs, order the data: 0.65, 0.67, 0.69, 0.71, 0.74, 0.75, 0.77, 0.85, 0.86. The median is the middle value, 0.74.
The interquartile range (IQR) is calculated as the difference between the upper quartile (UQ) and the lower quartile (LQ). LQ = 0.68, UQ = 0.81, so IQR = 0.81 - 0.68 = 0.13.
(iii) For the flat screen TVs, calculate the mean: