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M4U-9709-DF26-E-OP018 marks

E-OP01 · Least material for a closed cylinder

A closed cylinder has fixed volume \(128\pi\ \mathrm{cm^3}\), radius r cm and height h cm. Its total surface area is \(S=2\pi r^2+2\pi rh\).

Express S in terms of r only and give its feasible domain.

[2]

Find the stationary candidate and the corresponding cylinder dimensions.

[3]

Prove the candidate gives the global minimum surface area, and find that area.

[3]
Closed cylinderrhVolume = 128π cm³
Both circular ends count in the material area.

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