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One impossible algebraic root

8 written marks

Consider \(2\sin^2x-3\cos x=0\).

Part a · 3 marks

Rewrite this as a quadratic in \(u=\cos x\), then factor it.

Part b · 3 marks

Find all solutions for \(0\le x\lt 2\pi\), explaining any rejected ratio value.

Part c · 2 marks

Find the solution set instead on \(-\pi\le x\lt \pi\).

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