Year 7 - Q7.5.06
20552
Complete this efficient calculation: \(\displaystyle \frac{14}{15}\times\frac{25}{28}=\frac1{\square}\times\frac5{\triangle}\). The first denominator comes from \(28\) after cancelling with \(14\); the second comes from \(15\) after cancelling with \(25\). Then find the product.
Hint
Use common factors \(14\) and \(5\).