Browsing as Guest. Progress, bookmarks and attempts are disabled.
Log in to track your work.
Feb/Mar 2020 p32 q3
1903
(a) By sketching a suitable pair of graphs, show that the equation \(\sec x = 2 - \frac{1}{2}x\) has exactly one root in the interval \(0 \leq x < \frac{1}{2}\pi\).
(b) Verify by calculation that this root lies between 0.8 and 1.
(c) Use the iterative formula \(x_{n+1} = \cos^{-1}\left(\frac{2}{4-x_n}\right)\) to determine the root correct to 2 decimal places. Give the result of each iteration to 4 decimal places.
Solution
(a) Sketch the graph \(y = \sec x\) and the line \(y = 2 - \frac{1}{2}x\). The intersection point in the interval \(0 \leq x < \frac{1}{2}\pi\) indicates the root. The graphs intersect exactly once in this interval.
(b) Calculate \(\sec(0.8) \approx 1.139\) and \(2 - \frac{1}{2}(0.8) = 1.6\). Calculate \(\sec(1) \approx 1.850\) and \(2 - \frac{1}{2}(1) = 1.5\). Since \(\sec(0.8) < 1.6\) and \(\sec(1) > 1.5\), the root lies between 0.8 and 1.