For equally spaced gradients, concurrent intercepts must also form an arithmetic sequence. The horizontal line’s intercept is the average of the other two, so it must be 0. The remaining intercepts can be assigned in two orders.

Set 1: \(y=-x+2,\ y=0,\ y=x-2\), meeting at \(\left(2,\ 0\right)\). Set 2: \(y=-x-2,\ y=0,\ y=x+2\), meeting at \(\left(-2,\ 0\right)\).

Answer

Set 1: \(y=-x+2,\ y=0,\ y=x-2\), meeting at \(\left(2,\ 0\right)\). Set 2: \(y=-x-2,\ y=0,\ y=x+2\), meeting at \(\left(-2,\ 0\right)\).