The curve with equation \(y = \frac{x^3}{e^x - 1}\) has a stationary point at \(x = p\), where \(p > 0\).

(a) Show that \(p = 3(1 - e^{-p})\).

(b) Verify by calculation that \(p\) lies between 2.5 and 3.

(c) Use an iterative formula based on the equation in part (a) to determine \(p\) correct to 2 decimal places. Give the result of each iteration to 4 decimal places.