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Quadratic trigonometric equations — problem 2 · Maths4U Original · 6 marks
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Maths4U Original · M4U-EXT-0606-FURTHER-TRIG-EQUATIONS-P02

Solve \(2 \sin^{2}{\left(x \right)} - \sin{\left(x \right)} - 1 = 0\) on \(\left[0, 2 \pi\right]\). Angles are radians.

  1. Factor the equation in \(\displaystyle u=\sin (nx)\) and state the valid u-values. [2]
  2. Find all solutions on the stated interval. [2]
  3. Find the number of distinct solutions. Explain your reasoning. [2]
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