Hint
The stated vertices are in boundary order. Use horizontal base w and vertical height h.
Worked solution
(a)
Use horizontal base w and vertical height h.
\(25\)
Answer: \(25\)
(b)
A diagonal halves the parallelogram area.
\(\displaystyle \frac{25}{2}\)
Answer: \(\displaystyle \frac{25}{2}\)
(c)
Use the two diagonal coordinate differences.
\(74\)
Answer: \(74\)
Maths4U indicative marking guidance
Maths4U indicative marking guidance, not an official mark scheme. Credit complete valid alternatives and consequential reasoning; an unexplained final answer does not earn a method mark.
(a) · 2 marks
- 1 mark: Use horizontal base w and vertical height h.
- 1 mark: Give the correct requested result, retaining signs, units and any domain restrictions.
Alternative methods: Any complete mathematically valid alternative method with the same restrictions and equivalent exact result is acceptable.
Common error: Do not use a sloping side as the height.
(b) · 2 marks
- 1 mark: A diagonal halves the parallelogram area.
- 1 mark: Give the correct requested result, retaining signs, units and any domain restrictions.
Alternative methods: Any complete mathematically valid alternative method with the same restrictions and equivalent exact result is acceptable.
Common error: The area of a triangle is half its base-height product.
(c) · 2 marks
- 1 mark: Use the two diagonal coordinate differences.
- 1 mark: Give the correct requested result, retaining signs, units and any domain restrictions.
Alternative methods: Any complete mathematically valid alternative method with the same restrictions and equivalent exact result is acceptable.
Common error: Do not use a sloping side as the height.
Total: 6 marks.