9709 P31 - Jun 2017 - Q3
1712
It is given that \(x = \ln(1-y) - \ln y\), where \(0 < y < 1\).
(i) Show that \(y = \frac{e^{-x}}{1 + e^{-x}}\).
(ii) Hence show that \(\int_0^1 y \, dx = \ln \left( \frac{2e}{e+1} \right)\).
Solutions locked. Please sign in with access to view them.