9709 P32 - Nov 2021 - Q9
1673
The equation of a curve is \(ye^{2x} - y^2 e^x = 2\).
(a) Show that \(\frac{dy}{dx} = \frac{2ye^x - y^2}{2y - e^x}\).
(b) Find the exact coordinates of the point on the curve where the tangent is parallel to the y-axis.
Solutions locked. Please sign in with access to view them.