9709 P32 - Jun 2010 - Q6
1663
The equation of a curve is
\(x \ln y = 2x + 1\).
- Show that \(\frac{dy}{dx} = -\frac{y}{x^2}\).
- Find the equation of the tangent to the curve at the point where \(y = 1\), giving your answer in the form \(ax + by + c = 0\).
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