(i) Express \(\sqrt{5} \cos x + 2 \sin x\) in the form \(R \cos(x - \alpha)\), where \(R > 0\) and \(0^\circ < \alpha < 90^\circ\), giving the value of \(\alpha\) correct to 2 decimal places.

(ii) Hence solve the equation \(\sqrt{5} \cos \frac{1}{2}x + 2 \sin \frac{1}{2}x = 1.2\), for \(0^\circ < x < 360^\circ\).