Use logarithms to solve the equation \(e^x = 3^{x-2}\), giving your answer correct to 3 decimal places.
Solution
Start with the equation \(e^x = 3^{x-2}\).
Take the natural logarithm of both sides: \(\ln(e^x) = \ln(3^{x-2})\).
Using the logarithm power rule, this becomes \(x \ln e = (x-2) \ln 3\).
Since \(\ln e = 1\), the equation simplifies to \(x = (x-2) \ln 3\).
Rearrange to solve for \(x\):
\(x = x \ln 3 - 2 \ln 3\)
\(x - x \ln 3 = -2 \ln 3\)
\(x(1 - \ln 3) = -2 \ln 3\)
\(x = \frac{-2 \ln 3}{1 - \ln 3}\)
Calculate \(x\) using a calculator to get \(x \approx 22.281\).
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