June 2018 p31 q1
1532
Showing all necessary working, solve the equation \(\ln(x^4 - 4) = 4 \ln x - \ln 4\), giving your answer correct to 2 decimal places.
Solution
Start with the equation:
\(\ln(x^4 - 4) = 4 \ln x - \ln 4\)
Use the logarithm property \(\ln a - \ln b = \ln \left( \frac{a}{b} \right)\):
\(\ln(x^4 - 4) = \ln \left( \frac{x^4}{4} \right)\)
Since the logarithms are equal, set the arguments equal:
\(x^4 - 4 = \frac{x^4}{4}\)
Multiply through by 4 to clear the fraction:
\(4(x^4 - 4) = x^4\)
Expand and simplify:
\(4x^4 - 16 = x^4\)
Rearrange to form a quadratic equation:
\(3x^4 = 16\)
Divide by 3:
\(x^4 = \frac{16}{3}\)
Take the fourth root of both sides:
\(x = \left( \frac{16}{3} \right)^{1/4}\)
Calculate the value:
\(x \approx 1.52\)
Log in to record attempts.