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0580 P41 - Nov 2016 - Q6 - 15 marks
15102
FootpathsABCD,northatA,AC180mAB220mAD170m angleDAC33degrees

AB = 220 m, AC = 180 m, AD = 170 m, \(\angle ACB=90^\circ\) and \(\angle DAC=33^\circ\).

(a) Calculate BC. [3]

(b) Calculate CD. [4]

(c) Find the shortest distance from D to AC. [2]

The bearing of D from A is 047°.

(d) Find the bearing of B from A. [3]

(e) Calculate the area of ABCD. [3]

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