Solve the equation
\(\frac{2^x + 1}{2^x - 1} = 5\),
giving your answer correct to 3 significant figures.
Solution
Start with the equation:
\(\frac{2^x + 1}{2^x - 1} = 5\)
Multiply both sides by \(2^x - 1\):
\(2^x + 1 = 5(2^x - 1)\)
Expand the right side:
\(2^x + 1 = 5 \cdot 2^x - 5\)
Rearrange the terms:
\(2^x + 1 = 5 \cdot 2^x - 5\)
\(1 + 5 = 5 \cdot 2^x - 2^x\)
\(6 = 4 \cdot 2^x\)
Divide both sides by 4:
\(2^x = \frac{6}{4} = 1.5\)
Take the logarithm base 2 of both sides:
\(x = \log_2(1.5)\)
Calculate \(x\) using a calculator:
\(x \approx 0.585\)
Thus, the solution is \(x = 0.585\) to 3 significant figures.
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