To solve the inequality \(2 - 3x < |x - 3|\), we consider the critical points where the expressions inside the absolute value change sign.

1. Consider the equation \(2 - 3x = x - 3\).

2. Solving for \(x\), we have:

\(2 - 3x = x - 3\)

\(2 + 3 = x + 3x\)

\(5 = 4x\)

\(x = -\frac{1}{2}\)

3. The critical value is \(x = -\frac{1}{2}\).

4. Test intervals around the critical point:

- For \(x > -\frac{1}{2}\), choose \(x = 0\):

\(2 - 3(0) < |0 - 3|\)

\(2 < 3\), which is true.

- For \(x < -\frac{1}{2}\), choose \(x = -1\):

\(2 - 3(-1) < |-1 - 3|\)

\(5 < 4\), which is false.

5. Therefore, the solution is \(x > -\frac{1}{2}\).