(a) The graph of \(y = |2x + 3|\) is a V-shaped graph with the vertex at the point where \(2x + 3 = 0\), which is \(x = -\frac{3}{2}\). The graph is symmetric about the vertical line through the vertex.

(b) To solve \(3x + 8 > |2x + 3|\), consider the two cases for the absolute value:

Case 1: \(3x + 8 > 2x + 3\)

Simplifying gives \(x > -5\).

Case 2: \(3x + 8 > -(2x + 3)\)

Simplifying gives \(3x + 8 > -2x - 3\), which leads to \(5x > -11\) and \(x > -\frac{11}{5}\).

The solution is the intersection of these two cases, which is \(x > -\frac{11}{5}\).