(i) Demonstrate that the equation \(\tan(30^\circ + \theta) = 2 \tan(60^\circ - \theta)\) can be expressed as \(\tan^2 \theta + (6 \sqrt{3}) \tan \theta - 5 = 0\).

(ii) Consequently, or by other means, solve the equation \(\tan(30^\circ + \theta) = 2 \tan(60^\circ - \theta)\) for \(0^\circ \leq \theta \leq 180^\circ\).