A curve is such that \(\frac{dy}{dx} = k - 2x\), where \(k\) is a constant.
(i) Given that the tangents to the curve at the points where \(x = 2\) and \(x = 3\) are perpendicular, find the value of \(k\). [4]
(ii) Given also that the curve passes through the point (4, 9), find the equation of the curve. [3]
Solution
(i) At \(x = 2\), the gradient \(m = k - 4\). At \(x = 3\), the gradient \(m = k - 6\). Since the tangents are perpendicular, \((k - 4)(k - 6) = -1\).
Solving \((k - 4)(k - 6) = -1\):
\(k^2 - 10k + 24 = -1\)
\(k^2 - 10k + 25 = 0\)
\((k - 5)^2 = 0\)
\(k = 5\)
(ii) Integrate \(\frac{dy}{dx} = 5 - 2x\) to find \(y\):
\(y = 5x - x^2 + c\)
Substitute the point (4, 9):
\(9 = 5(4) - 4^2 + c\)
\(9 = 20 - 16 + c\)
\(c = 5\)
Thus, the equation of the curve is \(y = 5x - x^2\).
Log in to record attempts.