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0580 P41 - Jun 2020 - Q7 - 17 marks
13301
Triangle ABC with north arrow angleBAC72 AB80 AC115

AB = 80 m, AC = 115 m and angle BAC = 72°.

(a) Show that BC = 118.1 m, correct to 1 decimal place. [3]

(b) Find angle ABC. [3]

(c(i)) The bearing of C from A is 147°. Find the bearing of A from B. [3]

(c(ii)) Find the bearing of B from C. [2]

(d) Mitchell runs from A to C in 35 seconds. Find his average speed in km/h. [3]

(e) Find the shortest distance from B to AC. [3]

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