A curve is such that \(\frac{dy}{dx} = 2x^2 - 5\). Given that the point \((3, 8)\) lies on the curve, find the equation of the curve.
Solution
To find the equation of the curve, we need to integrate the derivative \(\frac{dy}{dx} = 2x^2 - 5\).
Integrating, we get:
\(y = \int (2x^2 - 5) \, dx = \frac{2x^3}{3} - 5x + c\)
We use the point \((3, 8)\) to find the constant \(c\).
Substitute \(x = 3\) and \(y = 8\) into the equation:
\(8 = \frac{2(3)^3}{3} - 5(3) + c\)
\(8 = \frac{54}{3} - 15 + c\)
\(8 = 18 - 15 + c\)
\(8 = 3 + c\)
\(c = 5\)
Thus, the equation of the curve is:
\(y = \frac{2x^3}{3} - 5x + 5\)
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