A curve is such that \(\frac{dy}{dx} = -x^2 + 5x - 4\).
Given that the curve passes through the point (6, 2), find the equation of the curve.
Solution
To find the equation of the curve, we need to integrate the derivative \(\frac{dy}{dx} = -x^2 + 5x - 4\).
Integrating term by term, we have:
\(y = \int (-x^2 + 5x - 4) \, dx = \int -x^2 \, dx + \int 5x \, dx - \int 4 \, dx\).
This gives:
\(y = -\frac{x^3}{3} + \frac{5x^2}{2} - 4x + c\), where \(c\) is the constant of integration.
We use the point (6, 2) to find \(c\):
\(2 = -\frac{6^3}{3} + \frac{5 \times 6^2}{2} - 4 \times 6 + c\).
\(2 = -72 + 90 - 24 + c\).
\(2 = -6 + c\).
\(c = 8\).
Thus, the equation of the curve is \(y = -\frac{x^3}{3} + \frac{5x^2}{2} - 4x + 8\).
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