Find \(\int \left( x + \frac{1}{x} \right)^2 \, dx\).
Solution
First, expand the integrand:
\(\left( x + \frac{1}{x} \right)^2 = x^2 + 2 \cdot x \cdot \frac{1}{x} + \left( \frac{1}{x} \right)^2 = x^2 + 2 + \frac{1}{x^2}\).
Now, integrate each term separately:
\(\int x^2 \, dx = \frac{x^3}{3} + C_1\)
\(\int 2 \, dx = 2x + C_2\)
\(\int \frac{1}{x^2} \, dx = \int x^{-2} \, dx = -x^{-1} + C_3 = -\frac{1}{x} + C_3\)
Combine the results:
\(\int \left( x + \frac{1}{x} \right)^2 \, dx = \frac{x^3}{3} - \frac{1}{x} + 2x + C\)
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