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Problem 1135
1135
A curve is such that \(\frac{dy}{dx} = \frac{6}{(3x-2)^3}\) and \(A(1, -3)\) lies on the curve. A point is moving along the curve and at \(A\) the \(y\)-coordinate of the point is increasing at 3 units per second.
Find the rate of increase at \(A\) of the \(x\)-coordinate of the point.
Solution
At \(x = 1\), \(\frac{dy}{dx} = 6\).
Using the chain rule, \(\frac{dx}{dt} = \left( \frac{dx}{dy} \times \frac{dy}{dt} \right)\).