0580 P42 - Nov 2025 - Q11 - 10 marks
11325
The table gives values of \(y=x^3-2x+3\), to 2 decimal places where needed.
| x | −2 | −1.5 | −1 | −0.5 | 0 | 0.5 | 1 | 1.5 | 2 |
|---|---|---|---|---|---|---|---|---|---|
| y | −1 | … | 4 | 3.88 | 3 | 2.13 | 2 | … | 7 |
(a) Complete the table. [2]
(b) Draw the graph for \(-2\le x\le2\). [4]
(c) By drawing a suitable straight line, solve \(x^3-2.5x+1=0\). [4]
