A curve has equation \(y = \frac{k}{x}\). Given that the gradient of the curve is \(-3\) when \(x = 2\), find the value of the constant \(k\).
Solution
The equation of the curve is \(y = \frac{k}{x}\). To find the gradient, we differentiate \(y\) with respect to \(x\).
\(\frac{dy}{dx} = -\frac{k}{x^2}\).
We are given that the gradient \(\frac{dy}{dx} = -3\) when \(x = 2\).
Substitute \(x = 2\) into the derivative:
\(-\frac{k}{2^2} = -3\).
Simplify:
\(-\frac{k}{4} = -3\).
Multiply both sides by \(-4\):
\(k = 12\).
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