(a) Approximate \(B(200,0.016)\) by \(X\sim\operatorname{Po}(3.2)\), since \(np=200(0.016)=3.2\). Then \[P(X>3)=1-e^{-3.2}\left(1+3.2+\frac{3.2^2}{2!}+\frac{3.2^3}{3!}\right)\approx0.397.\]

(b) The number of trials is large, \(n=200>50\), and the success probability is small, \(p=0.016<0.1\). Also \(np=3.2<5\). These support a Poisson approximation.