Centre, radius
Determine the centre and radius: \( x^2 + y^2 - x - 10y + 5 = 0 \)
Solution:
Group terms:
\[
(x^2 - x) + (y^2 - 10y) = -5
\]
Complete the square:
\[
(x^2 - x + \tfrac{1}{4}) + (y^2 - 10y + 25) = -5 + \tfrac{1}{4} + 25
\]
\[
(x - \tfrac{1}{2})^2 + (y - 5)^2 = \tfrac{81}{4}
\]
\(\text{Centre: }(\tfrac{1}{2},\,5), \quad \text{Radius: }\tfrac{9}{2}\)