\(\sqrt{2}\cdot\sqrt{8}=\sqrt{16}=4\).

Then \(4-1{,}25=2{,}75\).

\(\dfrac{\sqrt{200}}{\sqrt{2}}=\sqrt{\dfrac{200}{2}}=\sqrt{100}=10\).

Then \(10-0{,}2=9{,}8\).

\(\sqrt{0{,}036}\cdot\sqrt{10}=\sqrt{0{,}36}=0{,}6\).

Then \(2{,}1-0{,}6=1{,}5\).

\(\sqrt{49}=7\).

\(0{,}5^{5}:0{,}5^{3}=0{,}5^{5-3}=0{,}5^{2}=0{,}25\).

Then \(7-0{,}25=6{,}75\).

\(\sqrt{3}\cdot\sqrt{12}=\sqrt{36}=6\).

Then \(6-5{,}45=0{,}55\).

\(\dfrac{\sqrt{800}}{\sqrt{2}}=\sqrt{400}=20\).

\(\sqrt{9}=3\).

Then \(20+3=23\).

\(\dfrac{\sqrt{0{,}9}}{\sqrt{10}}=\sqrt{0{,}09}=0{,}3\).

Then \(3{,}2-0{,}3=2{,}9\).

\(\sqrt{64}=8\).

\(0{,}1^{8}:0{,}1^{6}=0{,}1^{8-6}=0{,}1^{2}=0{,}01\).

Then \(8-0{,}01=7{,}99\).

\(\sqrt{2}\cdot\sqrt{50}=\sqrt{100}=10\).

Then \(10-7{,}25=2{,}75\).

\(\sqrt{81}=9\), \(\sqrt{4}=2\), so \(3\sqrt{4}=6\).

Numerator: \(9+6=15\).

Denominator: \(\sqrt{100}=10\).

Then \(\dfrac{15}{10}=1{,}5\).

\(\sqrt{0{,}32}\cdot\sqrt{2}=\sqrt{0{,}64}=0{,}8\).

Then \(4{,}3-0{,}8=3{,}5\).

\(\sqrt{16}=4\).

\(0{,}3^{12}:0{,}3^{10}=0{,}3^{2}=0{,}09\).

Then \(4+0{,}09=4{,}09\).

\(\sqrt{2}\cdot\sqrt{18}=\sqrt{36}=6\).

Then \(6-2{,}05=3{,}95\).

\(\sqrt{500}\cdot\sqrt{\frac{5}{4}}=\sqrt{500\cdot\frac{5}{4}}=\sqrt{625}=25\).

\(\sqrt{0{,}049}\cdot\sqrt{10}=\sqrt{0{,}49}=0{,}7\).

Then \(7{,}3-0{,}7=6{,}6\).

\(\sqrt{3}\cdot\sqrt{27}=\sqrt{81}=9\).

\(0{,}5^{6}:0{,}5^{5}=0{,}5^{1}=0{,}5\).

Then \(9-0{,}5=8{,}5\).