Maths4U
Menu
← Back to Chapter
Browsing as Guest. Answer checking, progress and bookmarks are disabled. Log in to track your work.

Practice — General Motion in a Straight Line • Acceleration as the Derivative of Velocity with Respect to Time

Acceleration from velocity: check 1
Difficulty: ★★☆
5949
Info
M4U-EXT-QP-9709-M1-VELOCITY-DERIVATIVE-O1

Maths4U Original · Short practice

The signed velocity is \(v=t^{2} - 4 t + 8\) m/s for \(0\le t\le 4\), with t in seconds.

Find the acceleration at \(\displaystyle t=4 s\), in \(\displaystyle \frac{m}{s^{2}}\).

Enter one exact number or fraction unless the question specifies rounding. Use the requested units and positive direction; enter the number without its unit. Angles here use degrees. Give full reasoning separately for written problems.

Log in to check answers and record progress. You can still view solutions.
Acceleration from velocity: review variant 1
Difficulty: ★★☆
5950
Info
M4U-EXT-QP-9709-M1-VELOCITY-DERIVATIVE-O1-V1

Maths4U Original · Short practice

The signed velocity is \(v=2 t^{2} - 12 t + 23\) m/s for \(0\le t\le 6\), with t in seconds.

Find the acceleration at \(\displaystyle t=6 s\), in \(\displaystyle \frac{m}{s^{2}}\).

Enter one exact number or fraction unless the question specifies rounding. Use the requested units and positive direction; enter the number without its unit. Angles here use degrees. Give full reasoning separately for written problems.

Log in to check answers and record progress. You can still view solutions.
Acceleration from velocity: check 2
Difficulty: ★★☆
5951
Info
M4U-EXT-QP-9709-M1-VELOCITY-DERIVATIVE-O2

Maths4U Original · Short practice

The signed velocity is \(v=2 t^{2} - 12 t + 23\) m/s for \(0\le t\le 6\), with t in seconds.

Find the time when acceleration is zero, in s.

Enter one exact number or fraction unless the question specifies rounding. Use the requested units and positive direction; enter the number without its unit. Angles here use degrees. Give full reasoning separately for written problems.

Log in to check answers and record progress. You can still view solutions.
Acceleration from velocity: review variant 2
Difficulty: ★★☆
5952
Info
M4U-EXT-QP-9709-M1-VELOCITY-DERIVATIVE-O2-V1

Maths4U Original · Short practice

The signed velocity is \(v=3 t^{2} - 24 t + 54\) m/s for \(0\le t\le 5\), with t in seconds.

Find the time when acceleration is zero, in s.

Enter one exact number or fraction unless the question specifies rounding. Use the requested units and positive direction; enter the number without its unit. Angles here use degrees. Give full reasoning separately for written problems.

Log in to check answers and record progress. You can still view solutions.
Acceleration from velocity: check 3
Difficulty: ★★☆
5953
Info
M4U-EXT-QP-9709-M1-VELOCITY-DERIVATIVE-O3

Maths4U Original · Short practice

The signed velocity is \(v=3 t^{2} - 24 t + 54\) m/s for \(0\le t\le 5\), with t in seconds.

Find the minimum speed on the stated interval, in m/s.

Enter one exact number or fraction unless the question specifies rounding. Use the requested units and positive direction; enter the number without its unit. Angles here use degrees. Give full reasoning separately for written problems.

Log in to check answers and record progress. You can still view solutions.
Acceleration from velocity: review variant 3
Difficulty: ★★☆
5954
Info
M4U-EXT-QP-9709-M1-VELOCITY-DERIVATIVE-O3-V1

Maths4U Original · Short practice

The signed velocity is \(v=4 t^{2} - 40 t + 107\) m/s for \(0\le t\le 7\), with t in seconds.

Find the minimum speed on the stated interval, in m/s.

Enter one exact number or fraction unless the question specifies rounding. Use the requested units and positive direction; enter the number without its unit. Angles here use degrees. Give full reasoning separately for written problems.

Log in to check answers and record progress. You can still view solutions.
Acceleration from velocity: check 4
Difficulty: ★★☆
5955
Info
M4U-EXT-QP-9709-M1-VELOCITY-DERIVATIVE-O4

Maths4U Original · Short practice

The signed velocity is \(v=4 t^{2} - 40 t + 107\) m/s for \(0\le t\le 7\), with t in seconds.

Find the initial acceleration in \(\displaystyle \frac{m}{s^{2}}\).

Enter one exact number or fraction unless the question specifies rounding. Use the requested units and positive direction; enter the number without its unit. Angles here use degrees. Give full reasoning separately for written problems.

Log in to check answers and record progress. You can still view solutions.
Acceleration from velocity: review variant 4
Difficulty: ★★☆
5956
Info
M4U-EXT-QP-9709-M1-VELOCITY-DERIVATIVE-O4-V1

Maths4U Original · Short practice

The signed velocity is \(v=t^{2} - 4 t + 12\) m/s for \(0\le t\le 5\), with t in seconds.

Find the initial acceleration in \(\displaystyle \frac{m}{s^{2}}\).

Enter one exact number or fraction unless the question specifies rounding. Use the requested units and positive direction; enter the number without its unit. Angles here use degrees. Give full reasoning separately for written problems.

Log in to check answers and record progress. You can still view solutions.
No questions left in this filter.