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Practice — The normal distribution • Modelling with the normal distribution

Modelling with the normal distribution: check 1
Difficulty: ★★☆
2861
Info
M4U-EXT-QP-9709-S1-T154-O1

Maths4U Original · Short practice

A normal X satisfies \(\displaystyle P(X\le \frac{75}{2})= \Phi (- \frac{1}{2}), \ P(X\le \frac{213}{5})= \Phi (\frac{6}{5})\). Here Φ is the standard normal CDF.

Find the standard deviation of X.

Enter one number or fraction. Use at least six decimal places when needed; a distribution calculator may be used for probabilities.

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Modelling with the normal distribution: review variant 1
Difficulty: ★★☆
2862
Info
M4U-EXT-QP-9709-S1-T154-O1-V1

Maths4U Original · Short practice

A normal X satisfies \(\displaystyle P(X\le 38)= \Phi (- \frac{1}{2}), \ P(X\le \frac{224}{5})= \Phi (\frac{6}{5})\). Here Φ is the standard normal CDF.

Find the standard deviation of X.

Enter one number or fraction. Use at least six decimal places when needed; a distribution calculator may be used for probabilities.

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Modelling with the normal distribution: check 2
Difficulty: ★★☆
2863
Info
M4U-EXT-QP-9709-S1-T154-O2

Maths4U Original · Short practice

A normal X satisfies \(\displaystyle P(X\le 38)= \Phi (- \frac{1}{2}), \ P(X\le \frac{224}{5})= \Phi (\frac{6}{5})\). Here Φ is the standard normal CDF.

Find the mean of X.

Enter one number or fraction. Use at least six decimal places when needed; a distribution calculator may be used for probabilities.

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Modelling with the normal distribution: review variant 2
Difficulty: ★★☆
2864
Info
M4U-EXT-QP-9709-S1-T154-O2-V1

Maths4U Original · Short practice

A normal X satisfies \(\displaystyle P(X\le \frac{77}{2})= \Phi (- \frac{1}{2}), \ P(X\le 47)= \Phi (\frac{6}{5})\). Here Φ is the standard normal CDF.

Find the mean of X.

Enter one number or fraction. Use at least six decimal places when needed; a distribution calculator may be used for probabilities.

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Modelling with the normal distribution: check 3
Difficulty: ★★☆
2865
Info
M4U-EXT-QP-9709-S1-T154-O3

Maths4U Original · Short practice

A normal X satisfies \(\displaystyle P(X\le \frac{77}{2})= \Phi (- \frac{1}{2}), \ P(X\le 47)= \Phi (\frac{6}{5})\). Here Φ is the standard normal CDF.

Find P(X>40).

Enter one number or fraction. Use at least six decimal places when needed; a distribution calculator may be used for probabilities.

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Modelling with the normal distribution: review variant 3
Difficulty: ★★☆
2866
Info
M4U-EXT-QP-9709-S1-T154-O3-V1

Maths4U Original · Short practice

A normal X satisfies \(\displaystyle P(X\le 41)= \Phi (- \frac{1}{2}), \ P(X\le \frac{222}{5})= \Phi (\frac{6}{5})\). Here Φ is the standard normal CDF.

Find P(X>40).

Enter one number or fraction. Use at least six decimal places when needed; a distribution calculator may be used for probabilities.

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Modelling with the normal distribution: check 4
Difficulty: ★★☆
2867
Info
M4U-EXT-QP-9709-S1-T154-O4

Maths4U Original · Short practice

A normal X satisfies \(\displaystyle P(X\le 41)= \Phi (- \frac{1}{2}), \ P(X\le \frac{222}{5})= \Phi (\frac{6}{5})\). Here Φ is the standard normal CDF.

Find the 90th percentile of X.

Enter one number or fraction. Use at least six decimal places when needed; a distribution calculator may be used for probabilities.

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Modelling with the normal distribution: review variant 4
Difficulty: ★★☆
2868
Info
M4U-EXT-QP-9709-S1-T154-O4-V1

Maths4U Original · Short practice

A normal X satisfies \(\displaystyle P(X\le \frac{83}{2})= \Phi (- \frac{1}{2}), \ P(X\le \frac{233}{5})= \Phi (\frac{6}{5})\). Here Φ is the standard normal CDF.

Find the 90th percentile of X.

Enter one number or fraction. Use at least six decimal places when needed; a distribution calculator may be used for probabilities.

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