\[(x-2)(x-5)=0\] \[x=2,x=5\]

\[(x-3)(x-4)=0\] \[x=3,x=4\]

\[(x+2)(x-10)=0\] \[x=-2,x=10\]

We look for two numbers that multiply to \(12\) and add up to \(-7\): \[ -3 \times -4 = 12 \quad \text{and} \quad -3 + -4 = -7 \] Factor: \[ x^2 - 7x + 12 = (x - 3)(x - 4) = 0 \] Therefore: \[ x - 3 = 0 \quad \Rightarrow \quad x = 3 \] \[ x - 4 = 0 \quad \Rightarrow \quad x = 4 \] **Answer:** \( x = 3 \) or \( x = 4 \)